裂差和裂和的公式是1/n(n+1)=1/n-1/(n+1),1/(2n-1)(2n+1)=1/2[1/(2n-1)-1/(2n+1)],1/n(n+1)(n+2)=1/2[1/n(n+1)-1/(n+1)(n+2)],1/(√a+√b)=[1/(a-b)](√a
裂差和裂和的公式是1/n(n+1)=1/n-1/(n+1),1/(2n-1)(2n+1)=1/2[1/(2n-1)-1/(2n+1)],1/n(n+1)(n+2)=1/2[1/n(n+1)-1/(n+1)(n+2)],1/(√a+√b)=[1/(a-b)](√a