解,在梯形ABCD中,AB‖CD,AB<CD,AD丄CD,S梯形的面积等于(AB十CD)乄AD/2
证明,取BC中点E,连结AE交DC延长线于H,则????EAB≌????EHC,则,CH=AB,梯形ABCD的面积等于????ADH的面积。S????ADH=DH乄AD/2=(AB十CD)乄AD/2
解,在梯形ABCD中,AB‖CD,AB<CD,AD丄CD,S梯形的面积等于(AB十CD)乄AD/2
证明,取BC中点E,连结AE交DC延长线于H,则????EAB≌????EHC,则,CH=AB,梯形ABCD的面积等于????ADH的面积。S????ADH=DH乄AD/2=(AB十CD)乄AD/2