
A是一来个对称矩阵,所以它的逆源矩阵也是对称矩阵
设A的逆矩阵是[a,b;b,a]
根据两互逆矩阵的乘积是单位矩阵,所以有
[(50-x)/30,(20-x)/30; (20-x)/30,(50-x)/30][a,b;b,a]
=(1/30)[(50-x)a+(20-x)b,(50-x)b+(20-x)a;(20-x)a+(50-x)b,(20-x)b+(50-x)a]
=[1,0;0,1]

A是一来个对称矩阵,所以它的逆源矩阵也是对称矩阵
设A的逆矩阵是[a,b;b,a]
根据两互逆矩阵的乘积是单位矩阵,所以有
[(50-x)/30,(20-x)/30; (20-x)/30,(50-x)/30][a,b;b,a]
=(1/30)[(50-x)a+(20-x)b,(50-x)b+(20-x)a;(20-x)a+(50-x)b,(20-x)b+(50-x)a]
=[1,0;0,1]