解:∵y=tan(-x-π/6)=-tan(x+π/6) 由kπ-π/2<x+π/6<kπ+π/2,(k是整数) → kπ-2π/3<x<kπ+π/3(k是整数) ∴y=tan(-x-π/6)的单调递减区间是(kπ-2π/3,kπ+π/3)(k是整数)。
解:∵y=tan(-x-π/6)=-tan(x+π/6) 由kπ-π/2<x+π/6<kπ+π/2,(k是整数) → kπ-2π/3<x<kπ+π/3(k是整数) ∴y=tan(-x-π/6)的单调递减区间是(kπ-2π/3,kπ+π/3)(k是整数)。